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[quote="JeremyC"]Thats an old school sony. So its a decent little amp.
That being said, its not 2 ohm's bridged capable. You can run it in 2 ohm's stereo, but not 2 ohm's bridged.
So why would you want to bridge it and run 4 speakers? Its really not designed for that. Its designed to be used as a 3 or 4 channel amp. Two high pass chanels on the front, and a single (or two) low power subs in the rear.
[url]http://www.docs.sony.com/release/XM4045.PDF[/url][/quote]

Each speaker is 4ohm though. Would it change the ohms by putting all 4 positive and negative on the one bridge?

The reason I am trying to use it is because it's the only HPF amp I have.

I will just run the doors off of it and the dash on the head unit then for now till I get a proper 4 channel HPF amp?

Thats an old school sony. So its a decent little amp.

That being said, its not 2 ohm's bridged capable. You can run it in 2 ohm's stereo, but not 2 ohm's bridged.

So why would you want to bridge it and run 4 speakers? Its really not designed for that. Its designed to be used as a 3 or 4 channel amp. Two high pass chanels on the front, and a single (or two) low power subs in the rear.

[url]http://www.docs.sony.com/release/XM4045.PDF[/url]

[quote="loudwagon15s"]if you were running 4 sets of 4 ohm speakers[/quote]

I have 4 4 ohm speakers. I assume one set = 2?

[quote="loudwagon15s"] you could run a pair in parallel to 2 ohms and run 2 ohm stereo[/quote]

How do I do that?

[quote="loudwagon15s"]but it is a sony, so anything can happen
[/quote]

I thought this was before sony went to "xplod" (before they made crap amps)

if you were running 4 sets of 4 ohm speakers you could run a pair in parallel to 2 ohms and run 2 ohm stereo, and yes theoretically it would be best to get the most power from this amp safely, but it is a sony, so anything can happen

I have a sony xm-4045.

It has 2 high pass channels @ 40w and one bridged at 100w

Would it be bad to run 4 speakers off of that one bridge?

Edit: also, what would this amp typically be used for/best for?