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calculating enclosure..
Posted: Sat Jul 09, 2005 8:52 pm
by Darthness
I'm wondering how i'd calculate the size of n enclouser... based on either dimensions i already have, or from the volume i want.. ie, 1.8^3 sealed, 3/4" MDF
Posted: Sat Jul 09, 2005 10:11 pm
by smgreen20
What is your max LxWxH?
Internally, 20 x 16 x 9.75, externaly 21.5 x 17.5 x 11.25
Posted: Sun Jul 10, 2005 5:55 am
by Ryan from Ohio
wxhxl divided by 1728= cubic feet
Posted: Sun Jul 10, 2005 7:51 am
by Darthness
hrm, thats oddd... when i do wxhxl divede by 1728, i get about 8.5 cu ft. i'm pretty sure 8.5 cubic feet would run into my front seats, lol.
edit: this is for the maximum sized box i'm willing to put in..22"x39.5"x17"
Posted: Sun Jul 10, 2005 9:07 am
by jonnyb
22" by 40" by 20" is pretty damn huge... and 8.5 cubic foot is right.
my box that is 6" by 12" by 12" is .5 cubic feet.
Posted: Sun Jul 10, 2005 7:52 pm
by Darthness
hrm, that just doesn't seem right to me, i didn't think i had 8.5 cuft in my trunk. i fugured it was much smaller for some reason.
Well shit on me.
Posted: Fri Jul 15, 2005 11:26 pm
by Audiophile
shit son!! the box in my truck is 6.5 deep, 36 long, and 16 high and that shit's 1.97 cubic feet! 22x40x17 is HUGE!! 22" deep is HUGE!! lol
Posted: Sat Jul 16, 2005 6:23 am
by Darthness
i couldn't actually get a 8.5cuft box in there thoguh, i don't think i'td fit through the trunk opening. althoguh, i probably could go through the back seats.
Posted: Sat Jul 16, 2005 10:03 am
by Audiophile
build it while it's in the trunk
lol